2 cars of identical overall mass are in a race on a straight track.

 

Car A has 10% of it's mass in the body and 90% of it's mass in the wheels (hypothetically)

 

Car B has 90% of it's mass in the body and 10% of it's mass in the wheels (hypothetically)

 

Which car will win assuming they both have the same power and are driven identically etc. ?

 

I think car B would win (but am not certain).

I see you medication has run out again Nelson, you want me to pop into Boots for you?

Car B will win. Less power needed to turn the wheels. I think? :confused:

2 cars of identical overall mass are in a race on a straight track.

 

Car A has 10% of it's mass in the body and 90% of it's mass in the wheels (hypothetically)

 

Car B has 90% of it's mass in the body and 10% of it's mass in the wheels (hypothetically)

 

Which car will win assuming they both have the same power and are driven identically etc. ?

 

I think car B would win (but am not certain).

 

 

Being a thick as pig shite, like I am ;), I would have thought that both cars haveing the same overall mass would both cross the line at the same time :confused: Or does that just show how thick I am :D

Or it could be car B :D

Interesting - my theory is that as any point on the wheels other than the centre moves further than any point on the rest of the car - therefore more force is required to move the wheels than an equivalent mass in the car body - therfore B wins ?

Or it could even be car A

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

TBH I havent a clue, but this is getting my post count up :rofl: :rofl: :rofl:

Being a thick as pig shite, like I am ;), I would have thought that both cars haveing the same overall mass would both cross the line at the same time :confused: Or does that just show how thick I am :D

 

That's what most people think (even clever ones) - but I think it's more complex (see above) :nelson:

Depends who's driving (hypothetically)

Is this a trick question??

Car B - You need more power to turn a tractor wheel than a bike wheel (heavier) therefore using a greater amount of engine power to do the same task.

not a trick question - assume eveything is identical except mass of cars and wheels.

 

I made up the question btw - latest drugs seem to be working :hyper: :rofl: :duffer:

How long are they racing for? As the speed increases, the car with the heavier wheels will slowly fall behind more and more. One thing you didn't mention - what are the frictional losses like on both cars? :D

 

Car B would win - as the speed increased the effort required to turn the wheels on car A would increase, where as on car B, the theoretical effort required would be the same at any speed...

 

Make sense?

assume frictional losses are the same - they wud b different, but this wud b a secondary (minor) factor. I have created an exaggerated (unrealistic) model to make a point.

forget about braking, handling, traction etc.

Frictional losses would cause car A to lose by even more :D

What colour are the cars?

The winner will be white

rust more like!

 

And Nelson!

 

Just shut up:D

the consencus here at work is that B would win - so I was right :hyper: :hyper: :bow:

 

this means that using lightweight alloys has a 2-fold benefit - reduced mass of overall car AND greater mechanical efficiency :duffer: ;)

OMG! Nelson is back on MASS, please kill me now!

b would win. less energy needed to get its rotating bits rotating so more to shove it forward.

car b would win, because A has a considerably greater unsprung mass, and (as people have said) the amount of energy used to start the wheel rotating would be grater, so i B would accelerate faster.

 

When both cars have reached their "top speed" the energy required to move them would be much the same.

 

When time to stopping comes, agaiun due to rotational mass car A would take longer to stop, and so would have to decelerate earlier.

 

Slow to accelerate + same top speed + slow to decelerate = LOSER

Nope, car A would be slower due to the higher rotating mass..... I think :D

The external force needed to accelerate both cars at the same rate in a frictionless environment would be the same.

 

You would need 9 times as much torque to accelerate the wheels of car A if both cars were to accelerate at the same rate.

 

If the power of the engines was the same in both cars then car B would be quicker everytime.

If any of the cars involved were Yamaha Blue Pearl and looked the dp's. Based on my own experiments and bearing in mind the harmonic resonance exuded at 9,000,000 mega decibells from the genetic componant behind the wheel. The blue car wether it is A or B could explode and therefore loose.

 

This conclusion is based on a practical experiment and only goes to show that however much money and Theory you apply to anything the principal of Sod will usually crop up and give you a good sodomizing. :o However if by any chance it doesn't, I would just like to say it fooking well should for raising such a sh1te question.

 

Now that'll up my posts and up yours :rofl:

Some of you were obviously bored 5hitless at work this afternoon........ :slap:

 

What's the matter, no female staff with low, tight fitting clothing to distract you ? :D :hyper:

 

Richard :smw:

Some of you were obviously bored 5hitless at work this afternoon........ :slap:

 

What's the matter, no female staff with low, tight fitting clothing to distract you ? :D :hyper:

 

Richard :smw:

 

In one word I would like to say "BARSTARD" :rofl:

 

Is it that obvious. No don't answer that :cry:

 

At least I found a Recon engine for less than 2 grand Today, but I'm not telling you where because I carn't pay for it until tommorrow. :bow: